(1+3a)+(a^2-2a)=

Solution for (1+3a)+(a^2-2a)= equation:

Simplifying
(1 + 3a) + (a2 + -2a) = 0

Remove parenthesis around (1 + 3a)
1 + 3a + (a2 + -2a) = 0

Reorder the terms:
1 + 3a + (-2a + a2) = 0

Remove parenthesis around (-2a + a2)
1 + 3a + -2a + a2 = 0

Combine like terms: 3a + -2a = 1a
1 + 1a + a2 = 0

Solving
1 + 1a + a2 = 0

Solving for variable 'a'.

Begin completing the square.

Move the constant term to the right:

Add '-1' to each side of the equation.
1 + 1a + -1 + a2 = 0 + -1

Reorder the terms:
1 + -1 + 1a + a2 = 0 + -1

Combine like terms: 1 + -1 = 0
0 + 1a + a2 = 0 + -1
1a + a2 = 0 + -1

Combine like terms: 0 + -1 = -1
1a + a2 = -1

The a term is 1a.  Take half its coefficient (0.5).
Square it (0.25) and add it to both sides.

Add '0.25' to each side of the equation.
a + 0.25 + a2 = -1 + 0.25

Reorder the terms:
0.25 + a + a2 = -1 + 0.25

Combine like terms: -1 + 0.25 = -0.75
0.25 + a + a2 = -0.75

Factor a perfect square on the left side:
(a + 0.5)(a + 0.5) = -0.75

Can't calculate square root of the right side.

The solution to this equation could not be determined.